Let the set of all values of
, for which both the roots of the equation
are negative real numbers, be the interval
. Then
is equal to
Text Solution
Verified by ExpertsA
To find the set of all values of
for which both roots of the equation
are negative real numbers, follow these steps:
Discriminant Condition:
The equation's discriminant
must be nonnegative for real roots:

Simplifying this:

This can be factored as:

Meaning
…… . (i)
Sum of Roots Condition:
The sum of the roots (which is
) must be negative:
… . (ii)
Product of Roots Condition:
The product of the roots
must be positive:
…… . (iii)
Determine the Valid Interval:
Combine the results from conditions (i), (ii), and (iii). From conditions (i) and (ii), we find
:
Intersection of
and
gives:

Calculate
:
With
and
, compute:

Therefore, the difference
is 5.
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